(x-3)^2+(-x-4)^2-(x-5)^2-x=24

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Solution for (x-3)^2+(-x-4)^2-(x-5)^2-x=24 equation:



(x-3)^2+(-x-4)^2-(x-5)^2-x=24
We move all terms to the left:
(x-3)^2+(-x-4)^2-(x-5)^2-x-(24)=0
We add all the numbers together, and all the variables
(x-3)^2+(-1x-4)^2-(x-5)^2-x-24=0
We add all the numbers together, and all the variables
-1x+(x-3)^2+(-1x-4)^2-(x-5)^2-24=0
We move all terms containing x to the left, all other terms to the right
-1x+(x-3)^2+(-1x-4)^2-(x-5)^2=24

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